3/7y^2+1/7y=4/7

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Solution for 3/7y^2+1/7y=4/7 equation: 


y in (-oo:+oo)

(3/7)*y^2+(1/7)*y = 4/7 // - 4/7

(3/7)*y^2+(1/7)*y-(4/7) = 0

(3/7)*y^2+(1/7)*y-4/7 = 0

3/7*y^2+1/7*y-4/7 = 0

DELTA = (1/7)^2-(-4/7*3/7*4)

DELTA = 1

DELTA > 0

y = (1^(1/2)-1/7)/(3/7*2) or y = (-1^(1/2)-1/7)/(3/7*2)

y = 1 or y = -4/3

y in { -4/3, 1 }

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